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ATM 1/d1 + 1/d2 = 2/R = 1/f

To: "James W. Burrows" <burrjaw@halcyon.com>, David Sayah <dsayah@ucla.edu>
Subject: ATM 1/d1 + 1/d2 = 2/R = 1/f
From: Richard Schwartz <richas@chelsea.ios.com>
Date: Sat, 28 Sep 96 18:30:36 -0500
Cc: ATM Mailing List <atm@shore.net>
Reply-To: Richard Schwartz <richas@chelsea.ios.com>
Sender: owner-atm@shore.net

-- [ From: Richard Schwartz * EMC.Ver #2.5.02 ] --

I screwed up in my previous posting, and the interfernal net does not allow
me to withdraw embarrassing messages after they have been thoughtlessly
launched.  In any case, the title shows the correct formula, and the
original conclusion that numerical computations will reveal negligible
difference still stands.

Flaming is not required; I am already in self-immolation.

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