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[ATM] What is that Image size in Calculations
Hi all
This is my first mail to the list so let me introduce myself
My name is George Nikolidakis and I am an amateur astronomer from Greece
Reentry I manage to finish a permanent roll-off observatory to house a 12"
LX200
Mainly for astrophotography purpose.
You can take a look for the observatory here
http://www.geocities.com/ginik_gr/NewObservetory
And also in some deep sky photos here
http://www.geocities.com/ginik_gr/EosDeepSky.htm
My problem is now that I don't have any telescope for optical observation
(star parties and campaigns)
So I decided to order a 20" f/4.5 primary from Pegasus optics in order to
build a truss tube telescope.
In my calculation about the size of secondary mirror one of the parameters
is the image size.
D=( L(D-I)) / F + I
Where I = image size , L = the distance from the Secondary to focal plane
.
D= Primary Size , F= focal lenght
I am not sure what it means, for example I like to full illuminate a 2"
eyepiece.
Is that means the image size it will be 2"?
Also L = the distance from the Secondary to focal plane .
The point for the focal plane it will be the base, I mean the low end of the
eyepiece ?
I have a few others questions but in the next days ... -:-)
Thanks
George Nikolidakis
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