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[ATM] Right house, wrong barn



And the moral of the story is "don't try to do math while composing...
especially trying to convert someone elses notation to your own"!


Richard F.L.R. Snashall wrote:
 >
 >
 > Vladimir Galogaza wrote:
 >
 >  > In this case general (ASCII) expression for the conic is
 >  >
 >  > z(x)=x^2/{R*[1+sqrt(1-(K+1)*(x^2/R^2)]}            (1)
 >  >
 >  > R stands for paraxial radius of curvature
 >  > K is conic constant ( -1 for parabola, 0 for circle)
 >  >
 >  > For given R and K and zone radius xo= yn
 >  > corresponding conic ordinate z(xo)=yc is
 >  > obtained from the conic expression (equation) (1)
 >  >
 >  > tangent to the conic z(x) in the point (xo,yo) is:
 >  >
 >  > t(x,xo,K) = d1z(xo)*(x-xo) + z(xo,K)
 >  >
 >  > normal to this tangent in the point (xo,yo) is:
 >  >
 >  > n(x,xo,K) = (-1/d1z(xo))*(x-xo) + z(xo)   ( this is the line you are
 > looking
 >  > for)
 >

S = (R/(K+1)) * ( 1 - sqrt( 1 - (K+1)*(yc/R)^2 ) )

Q = R * sqrt( 1 - (K+1)*(yc/R)^2 )

S + Q = (R/(K+1)) * ( 1 + K*sqrt( 1 - (K+1)*(yc/R)^2 ) )

yn/yc = (S + Q)/Q = 1/( (K+1)*sqrt( 1 - (K+1)*(yc/R)^2 ) ) + K/(K+1)

or:

yn/yc - K/(K+1) = 1/( (K+1)*sqrt( 1 - (K+1)*(yc/R)^2 ) )

or (squaring):

( yn/yc - K/(K+1) )^2 = 1/( (K+1)^2 * ( 1- (K+1)*(yc/R)^2 ) )

and (multiplying by yc^2 * (K+1)^2 * ( 1 - (K+1)*(yc/R)^2 ) )

( 1 - (K+1)*(yc/R)^2 ) * ( (K+1)*yn - K*yc )^2 = yc^2


Now, hopefully, this iteration is correct...

-- 

Rick S.

http://users.rcn.com/rflrs


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