Re: [ATM] ground ring diameter vs. mirror diameter

[Dave Smith <smithersscope@yahoo.com>]

> For the maximum diameter of support of a rocker box,
> the support 
> points should be at the corners.  For a square
> rocker box, this mean 
> that the ground ring diameter will be square root of
> two (~1.41) times 
> the rocker box width/length.

Yep, I've convinced myself this equation is correct
for square mirror boxes by doing the 3D design in
SolidWorks. Designing and positioning the flex rocker
(so as to avoid collisions with "attachment" bolts
and/or mirrorbox extrusions) insists that 1.41 is a
bit small for the ground ring. Gotta have a bit of
room for clearance. So my 32 inch inside diameter
ground ring is actually 1.58x the square mirrorbox
width (I'm using some nice dumpster-derived 1" thick
plywood). 1.5x seems to be a good approximation. It
just looks so stinkin' big! Like a cannon sitting on
the driveway!

BTW, SolidWorks is a phenomenal piece of 3D design
software. Steep learning curve, but literally
unlimited application! I highly recommend it.
Thanks All!
Dave

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