Re: [ATM] Hi resolution interferometry of mirror surface

["Jerry" <wa4guu@verizon.net>]

The Foucault appears to show the same defects in the small portion not in
the total darkness of the shadows. More Foucault images would be necessary,
but the corresponding defects can be seen. In the interferometery, at the
upper left diagonal of the box is a ridge that extends inward to the center
that looks to correspond to the streak inward in the Foucault image at about
the 11:30 clock position. You can trace the ridge across the top of the
center hole and to the upper right diagonal of the box. That corresponds to
the high that is slightly visible going to about 3 or 3:15 clock position on
the Foucault. There is a low at about 7:30 on the Foucault that you can see
matches the interferometry at the bottom right corner of the box. Using
those major features you can identify a number of corresponding features.

The Foucault alone tells me that this is far from a nice parabola. No knife
readings required, this mirror needs work, but it is a good example for
Dale's purpose. With more Foucault images to show more of the surface more
and more matches to the interferometry. 

How did I do Dale?

Jerry


-----Original Message-----
From: atm-bounces@atmlist.net [mailto:atm-bounces@atmlist.net] On Behalf Of
Dominic-Luc Webb
Sent: Tuesday, May 02, 2006 4:34 AM
To: ATM Superheros
Subject: Re: [ATM] Hi resolution interferometry of mirror surface


Impressive that you can see what appears to be large
deviations compared to a Foucault that looks to be
a very nice parabola.

I am curious if you could mark some of the extreme deviations
found in the interferogram against the Foucault?

I would also be interested in any info on your homemade rig....

Dominic-Luc Webb

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