Re: [ATM] perfect foucault results

["Bob May" <rmay@nethere.com>]

Did you take into account that the numbers for a moving source
are half the numbers for a stationary source???  If you
calculated the numbrs for a moving source (roc of each zone) then
the numbers are half of what the results should be for the
stationary source.  In addition, the numbers for a stationary
source will be slight different for very fast mirrors as you are
actually measuring a slight ellipsoid surface rather than a true
ROC  of what a parabola would be.
Bob May

rmay at nethere.com
http: slash /nav.to slash bobmay
http: slash /bobmay dot astronomy.net


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