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Re: [ATM] The zonal Foucault test is free of inherent correction bias
Ken Lowther wrote:
>> It results from the familiar relation for longitudinal aberration,
>> LA=h^2/R. If "h" is replaced by D/2 and R by 2FD, it becomes LA=D/8F. In
>> other words, longitudinal spherical of a paraboloid at r.o.c. is double
>> its sagitta (depth).
>
>
> I haven't played the equations for a while. What are h, R and D?
"h" is the zonal hight, R the r.o.c. and D the diameter of a mirror (F is
the F# of the mirror at infinity focus). Putting D/2 for "h" gives the total
longitudinal aberration at the r.o.c.
>> The easier way is simply to scale the focal zone geometry.
>> Doubling the mirror diameter will result in doubling of all linear
>> aberrations, including the transverse spherical. But the Airy disc
>> diameter (2.44LambdaF) won't change, resulting in doubling of the
>> relative blur size - and the wavefront aberration.
>>
> I though Airy disc size went down as per:
>
> r = 127.1/D (for yellow light in which Lambda = 0.00055mm)
>
> Where D is diameter, so the larger D the smaller the disc?
This is an angular value, in arc seconds. I'm not sure where it comes from,
being somewhere between the angular Airy disc radius (1.22Lambda/D in
radians, multiplied by 206,265 for arc seconds) and the full width at
half-maximum (FWHM=Lambda/D in radians).
In any case, angular size of the Airy disc diminishes with the increase in
aperture due to the increase in f.l. and, consequently, image scale. In
fact, given F#, physical dimensions of focal diffraction are just the same
in a 10cm and 10m aperture. It is only due to the change in the image scale
that its angular size diminishes, resulting in improved angular resolution.
Vlad
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