Re: [ATM] Pressure per square mm

[Dale Eason <atmpob@yahoo.com>]

I have been look at you derivation for the force on
the beam.  You have better calculus skill than I.  I
never had to use what I learned 35 years ago.

I had been thinking about the problem.  It seems to me
that your equations doesn't match one of your
conditions.  That is check condition #2 when L1 = L2. 
I had thought at that point that the force was all
directed at the fulcrum at the middle of the bar.  If
that was the case then the 4W/L1 term is wrong because
it indicates that every point over L1 would have that
force + some relating to x.

I made a simulator by suspending a rod from three
equal rubber bands when the band were spaced at each
end and the middle of the rod then their length was
equal (equal force on all rubber bands.)  When I move
one of the end rubber bands toward the middle it
streched longer than the middle and the other end
relaxed and was shorter than the middle.  This implied
to me that the end resting on the table has less force
on it than the middle resting on the edge of the
table.

Dale Eason

__________________________________
Do you Yahoo!?
Yahoo! Mail - More reliable, more storage, less spam
http://mail.yahoo.com
_______________________________________________
ATM mailing list http://www.atmlist.net/