Re: ATM 85 1/4?

[starlord@qnet.com (Slc.Dennis Bishop)]

>Since it says "R," it's probably a radius of curvature in inches.  So the
>focal distance would be half of that, or 42 5/8 inches.  Does that work out
>better?
>
>--Spencer Roedder
>
  well, with the main mirror where it is now, that puts the FP 2inchs
past the end of the tube, and I'id have to do away with the mirror
cell as from the  eyepice hold that would put the mirror almost
1/4inch past the rear of the tube. As Stargazer Steve is in Canada,
that's why I figured it in centameters.



*---------------------------------------------*
| Slc.Dennis Bishop Founder & Lifetime Member |
| SIAR (1971)   /  IAR (1995                  |
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