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Re: [ATM] Function question

Lawrence D. Lopez wrote:
> i think so.
> Largest value occurs when x and y don't cancel.
> for y = -x.
> 2x/sqrt(s*s+2x*x)
> make x >>s:
> 2x/sqrt(2x*x) = 2x/(sqrt(2)x) = 2/sqrt(2)= sqrt(2).
Yes, of course!  Thank you.  In terms of x' and y', rotated
clockwise from x and y by 45 degrees (if I did all my Cs and
Ss properly), that function is:

       sqrt( 2 ) * x' / sqrt( s^2 + x'^2 + y'^2 )
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