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Re: [ATM] convex secondary



Hi Jonathan,

Sunday, February 27, 2005, 7:04:55 AM, you wrote:


JL> I know the radius of curvature for the 4 inch secondary
JL> will be 34.5 inch and I know that it has to be an hyperbola
JL> but I didn't find the amount of correction that needs to be
JL> done.

The figures you give suggests that the focal plane is 2" in
front of the primary. If you are sure that is what you want then
the secondary needs a conic constant K = -4.000

-- 
Best regards,
 Richard                            mailto:cnc@cncservo.co.uk

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