Re: [ATM] Need a Chemistry guru! OT

["Marc Fokker" <ptp@extel.xs4all.nl>]

If this reaction takes place in plenty water, I don't expect the NaOH to 
form Na2O + H2.
But I didn't test it, and I'm not a guru.

Marc

----- Original Message ----- 
From: "Thomas Janstrom" <thomas@moiler.com>
To: "'ATM'" <atm@atmlist.net>; <atm_free@yahoogroups.com>
Sent: Sunday, December 30, 2007 8:11 AM
Subject: [ATM] Need a Chemistry guru! OT


> Hi All,
>
>
>
> I need a chemistry guru to help explain something that I'm observing in a
> hydroxide reaction.
>
>
>
> The basic reaction is: 6NaOH(aq) + 3Al(s) + 3H2O --> 2Al(OH)3(aq) + 3 Na2O
> + 3H2(g).
>
>
>
> However I'm observing the production of two gas streams, one is composed 
> of
> very fine (submicron) bubbles the other larger (1-2mm) bubbles. I should
> mention that there are two spectator metals present, platinum and cobalt.
>
>
>
> So my question (well one of them anyway!) is what is the second gas stream
> (I suspect O2), but more importantly why is it being produced?
>
>
>
> As this is quite off topic I'd prefer that respondents respond off list.
> Unless the moderators want to entertain a segway into the world of the
> atoms, that is!
>
>
>
> Cheers, Thomas.
>
>
>
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> 

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