vladimir wrote: > > K1: -1 > R1: unit > to secondary : [(1-k)R1]/2 = R3 > K2: -1+(1-k)^3 > R2: kR1 > to tertiary: kR1/(1-k) > K3: 0 Oops... R3 should be equal to the secondary-to-tertiary separation, R3=kR1/(1-k). Vlad _______________________________________________ ATM mailing list http://www.atmlist.net/