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Re: [ATM] Polar moment of inertia for a square tube?
Hi Tom,
Saturday, December 3, 2005, 4:31:03 AM, you wrote:
TK> Polar moment of inertia (resistance to twisting/torsion, not
TK> bending/moments) for a square tube:
TK> a^4/6 - b^4/6
TK> where a is outer width and b is inner width.
TK> Am I correct?
Yes.
--
Best regards,
Richard in the UK
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