Re: [ATM] Polar moment of inertia for a square tube?

["Tom Krajci" <tom_krajci@tularosa.net>]

Thanks for the various answers I received!

I want to make sure I have this right before I go farther.

Polar moment of inertia (resistance to twisting/torsion, not
bending/moments) for a square tube:
a^4/6 - b^4/6
where a is outer width and b is inner width.

See:  http://www.efunda.com/math/areas/rectangle.cfm
specifically the value for "Polar Moment of Inertia about the Zc axis"
...and make b and h equal, and simplify.

Am I correct?

Tom Krajci
Cloudcroft, New Mexico
http://overton2.tamu.edu/aset/krajci/



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