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Re:[ATM] Holographic Foucault null test



Dennis,Mauritz,

I'm not too sure if this is what you mean here Dennis, but it is actually
not the scatter from the mirror surface that puts the light in the higher (m
!= 0) order images, but the diffraction from the slit in the mask.
Also, wider slits cause lower intensity of these maxima, and ultimately the
intensity is 0.

/Arjan

<<<
>
>   Also, should this work equally well for mirrors that are
> already coated, or would the scattered light be at too low of
> an intensity to see the interference pattern at the m=1 position?
>

It works also for coated mirrors, the m=+-1 diffraction order
will always be about 40% intensity of the zero order, independent
of the mirror reflectivity.
(Just be a bit more careful when using lasers as lightsource since
the intensity can be too big.)
>>>

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