Re: [ATM] Why is it called a "flex rocker"?

["Vladimir Galogaza" <vladimir.galogaza@zg.htnet.hr>]

Dave,

You gave an explanation to question :Why is it called a "flex rocker"?
which I accepted until a gave it a second thaught.

>The design of the tri-dob is based on three bearing
>contact points. If one made a rigid rocker box,
>there's a good chance the OTA wouldn't sit down with
>equal pressure at each of the three bearing points. So
>when you build the rocker, it's just a simple frame
>that is intentionally flexible so that when the heavy
>OTA is placed on it, it "mashes" into contact with the
>three bearing points.

There was no mentioning of the Alt plane AND Azimuth plane as in
your last post quoted here:

>...if the azimuth bearings AND the alt bearings existed in
>the same plane, one could build an inflexible rocker
>that would function well. However, the "plane" of the
>rocker in the tridob actually has depth resulting from
>the positioning of the azimuth bearings below the
>rocker and alt bearings above the rocker.

I am not saying that your explanation is wrong. I only say that
I do not get it.
(Especially the notion :"if the azimuth bearings AND the alt bearings
existed in the same plane...")
Perhaps  others do, but I will be glad to have it explained in some other
way.( Mel in his response said :"The 'weakness' of the flex rocker is turned
into its strength - namely that the bearings maintain solid contact at all
times."
He did not said "azimuth bearings", just "bearings" which includes all
bearings)


Altitude bearings are not in one plain . And we can hardly put them
into one plane exactly because there are four of them,
 and they will certainly benefit from flexibility which is
subject of this thread, in order to seat properly, all four of them
simultaneously.
Three azimuthal bearings are always in certain plain and
whatever you do with flexibility (rigidity) of the rocker box they will
seat.
My conclusion is that flexibility of the rocker box will aid ONLY
in better conforming of Alt bearings. Contrary to the introductory
"explanation"
given as answer to the thread question (and as long as there are
only three azimuth bearings).

Dave, Mel, can you please straighten me up if I am wrong?

Vladimir.





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